Integrand size = 23, antiderivative size = 63 \[ \int \frac {\cos ^8(c+d x)}{(a+a \sin (c+d x))^{5/2}} \, dx=-\frac {8 a^2 \cos ^9(c+d x)}{99 d (a+a \sin (c+d x))^{9/2}}-\frac {2 a \cos ^9(c+d x)}{11 d (a+a \sin (c+d x))^{7/2}} \]
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Time = 0.09 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {2753, 2752} \[ \int \frac {\cos ^8(c+d x)}{(a+a \sin (c+d x))^{5/2}} \, dx=-\frac {8 a^2 \cos ^9(c+d x)}{99 d (a \sin (c+d x)+a)^{9/2}}-\frac {2 a \cos ^9(c+d x)}{11 d (a \sin (c+d x)+a)^{7/2}} \]
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Rule 2752
Rule 2753
Rubi steps \begin{align*} \text {integral}& = -\frac {2 a \cos ^9(c+d x)}{11 d (a+a \sin (c+d x))^{7/2}}+\frac {1}{11} (4 a) \int \frac {\cos ^8(c+d x)}{(a+a \sin (c+d x))^{7/2}} \, dx \\ & = -\frac {8 a^2 \cos ^9(c+d x)}{99 d (a+a \sin (c+d x))^{9/2}}-\frac {2 a \cos ^9(c+d x)}{11 d (a+a \sin (c+d x))^{7/2}} \\ \end{align*}
Time = 0.21 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.83 \[ \int \frac {\cos ^8(c+d x)}{(a+a \sin (c+d x))^{5/2}} \, dx=-\frac {2 \cos ^9(c+d x) \sqrt {a (1+\sin (c+d x))} (13+9 \sin (c+d x))}{99 a^3 d (1+\sin (c+d x))^5} \]
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Time = 0.60 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.90
method | result | size |
default | \(\frac {2 \left (1+\sin \left (d x +c \right )\right ) \left (\sin \left (d x +c \right )-1\right )^{5} \left (9 \sin \left (d x +c \right )+13\right )}{99 a^{2} \cos \left (d x +c \right ) \sqrt {a +a \sin \left (d x +c \right )}\, d}\) | \(57\) |
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Leaf count of result is larger than twice the leaf count of optimal. 161 vs. \(2 (55) = 110\).
Time = 0.28 (sec) , antiderivative size = 161, normalized size of antiderivative = 2.56 \[ \int \frac {\cos ^8(c+d x)}{(a+a \sin (c+d x))^{5/2}} \, dx=-\frac {2 \, {\left (9 \, \cos \left (d x + c\right )^{6} - 23 \, \cos \left (d x + c\right )^{5} - 52 \, \cos \left (d x + c\right )^{4} + 4 \, \cos \left (d x + c\right )^{3} - 8 \, \cos \left (d x + c\right )^{2} + {\left (9 \, \cos \left (d x + c\right )^{5} + 32 \, \cos \left (d x + c\right )^{4} - 20 \, \cos \left (d x + c\right )^{3} - 24 \, \cos \left (d x + c\right )^{2} - 32 \, \cos \left (d x + c\right ) - 64\right )} \sin \left (d x + c\right ) + 32 \, \cos \left (d x + c\right ) + 64\right )} \sqrt {a \sin \left (d x + c\right ) + a}}{99 \, {\left (a^{3} d \cos \left (d x + c\right ) + a^{3} d \sin \left (d x + c\right ) + a^{3} d\right )}} \]
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Timed out. \[ \int \frac {\cos ^8(c+d x)}{(a+a \sin (c+d x))^{5/2}} \, dx=\text {Timed out} \]
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\[ \int \frac {\cos ^8(c+d x)}{(a+a \sin (c+d x))^{5/2}} \, dx=\int { \frac {\cos \left (d x + c\right )^{8}}{{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac {5}{2}}} \,d x } \]
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none
Time = 0.30 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.08 \[ \int \frac {\cos ^8(c+d x)}{(a+a \sin (c+d x))^{5/2}} \, dx=-\frac {64 \, {\left (9 \, \sqrt {2} \sqrt {a} \sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} - 11 \, \sqrt {2} \sqrt {a} \sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9}\right )}}{99 \, a^{3} d \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} \]
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Timed out. \[ \int \frac {\cos ^8(c+d x)}{(a+a \sin (c+d x))^{5/2}} \, dx=\int \frac {{\cos \left (c+d\,x\right )}^8}{{\left (a+a\,\sin \left (c+d\,x\right )\right )}^{5/2}} \,d x \]
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